This is part 2 on free energies. (To return to part 1 ....)

MOLECULAR TRANSFORMATION CALCULATION:

Use the following free energy for the dynamics (Zwanzig, Berendsen, McCammon):

U* = lUB + (1-l)UA

where UA describes molecule A (in solution, etc.) and UB describes molecule B (in solution, etc.). Then

More general form:

U* = U*(UA,UB,l)
U*(UA,UB,
0) = UA
U*(UA,UB,
1) = Ub

Non-linear coupling of Lennard-Jones energy ("inflate"):

Use le, ls
Or le, ls3

and something similar for the electrostatic energy.


Molecular Transformation Calculation:
Solvation free energy.

Equilibrium between two states: Water + Solute(vapor) and Solute-in-water

Use the following free energy function for the dynamics:

U* = U(water-water) + U(solute) + lU(water-solute)

Dsolvation = kT ln [cvapor/cwater]

The ratio cvapor/cwater is the partition coefficient.


THERMODYNAMIC CYCLE:
Protein and different ligands

Protein + Ligand A <=> P.A has eqm.const. KA and free energy Db,A

Protein + Ligand B <=> P.B has eqm.const. KB and free energy Db,B

(e.g. two different inhibitors of an enzyme)

One computes this as the difference between the free energies for two transformations:


THERMODYNAMIC CYCLE.
Mutant and wild-type forms of protein with same ligand

WT Protein + Ligand <=> P+.L, has eqm.const. K+ and free energy D+

mutant Protein + Ligand => P-.L has eqm.const. K- and free energy D-

One computes this as the difference between the free energies for two transformations:


Multiple-Minima problem